Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 19 - Sections 19.1-19.12 - Exercises - Problems by Topic - Page 945: 31d

Answer

$^{13}_{7}N\ -->\ ^{13}_{6}C + ^{0}_{+1}e$

Work Step by Step

A Nitrogen-13 nuclide emits a positron causing one of its protons to turn into a neutron making it a Carbon-13 nuclide.
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