Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 19 - Sections 19.1-19.12 - Exercises - Problems by Topic - Page 945: 35c

Answer

$^{241}_{94}Pu → ^{241}_{95}Am + ^{0}_{-1}e$

Work Step by Step

Pu-241 undergoes Alpha decay to form Am-241
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