Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 14 - Sections 14.1-14.9 - Exercises - Problems by Topic - Page 689: 31c

Answer

$$K_c = 81.9$$

Work Step by Step

$$K_p = K_c (RT)^{\Delta n}$$ $\Delta n = n(products) - n(reactants) = (2) - (1 + 1) = 0$ $R = 0.08206 $ $T = 298$ $K_p = 81.9$ $$K_c = \frac{K_p}{(RT)^{\Delta n}} = \frac{81.9}{(0.08206 \times 298)^0 } = 81.9$$
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