Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 14 - Sections 14.1-14.9 - Exercises - Problems by Topic - Page 689: 27a

Answer

$$K_p = 4.42 \times 10^{-5}$$ The reactants are favored at equilibrium.

Work Step by Step

- Since the reaction was inverted, the new equilibrium constant will be equal to the multiplicative inverse of the original one: $$K_p = \frac 1{2.26 \times 10^{4}} = 4.42 \times 10^{-5}$$ - Since $K_p \lt 1$, the reactants will be favored at equilibrium.
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