Answer
$Kp=2.066\times10^{-13}$
The reactants are favored at equilibrium.
Work Step by Step
Since the reaction was inverted and also multiplied by 2, the new equilibrium constant will be equal to the multiplicative inverse of the square of original one.
$Kp=\frac{1}{(2.2\times10^{6})^{2}}$=$2.066\times10^{-13}$
Since $Kp<1$ ,the reactants will be favored at equilibrium.
