Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Challenge Problems - Page 42: 135

Answer

Energy is represented in Joules (J), which is equal to $kg \space m^2/s^2$ $\frac{1}{2} mv^2 : (kg) (m/s)^2 = kg \space m^2 / s^2 $ $\frac 32 PV: (kg/(s^2m))(m^3) = kg \space m^2 / s^2$

Work Step by Step

The SI unit for each term is: $m : kg$ $v : m/s$ $a : m/s^2$ $A = m^2$ $P = F /A = (m \times a)/ A :(kg) \times (m/s^2)/(m^2) = (kg \space m/s^2)/m^2 = kg/(s^2m)$ $V : m^3$ Energy is represented in Joules (J), which is equal to $kg \space m^2/s^2$ Thus: $\frac{1}{2} mv^2 : (kg) (m/s)^2 = kg \space m^2 / s^2 $ And: $\frac 32 PV: (kg/(s^2m))(m^3) = kg \space m^2 / s^2$
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