Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Challenge Problems - Page 42: 134

Answer

centimeter

Work Step by Step

$1\,dyne = 10^{-5}N$ That is, $g\times\frac{unit\,of\,length}{s^{2}}= 10^{-5} kg\,ms^{-2}$ or the unit of length=$10^{-5} kg\,ms^{-2}\times g^{-1}s^{2}$ $=10^{-5}\times10^{3}m=10^{-2}m= cm$
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