Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 7 - Quantum Theory and the Electronic Structure of Atoms - Questions & Problems - Page 317: 7.63

Answer

Please see the work below.

Work Step by Step

The total number of electrons in each orbital can be calculated using the formula $2\times(2l + 1)$. The s orbital has an $l$ value = 0. Therefore, the total number of electrons that can be accommodated = $2\times(2 \times 0 + 1) = 2$ . The p orbital has an $l$ value = 1 [There are three degenerate p orbitals]. Therefore, the total number of electrons that can be accommodated = $2\times(2 \times 1 + 1) = 6 $. The d orbital has $l$ value = 2 [There are five degenerate d orbitals]. Therefore, the total number of electrons that can be accommodated = $2\times(2 \times 2 + 1) = 10 $.
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