Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 7 - Quantum Theory and the Electronic Structure of Atoms - Questions & Problems - Page 317: 7.42

Answer

$1.7\times10^{-23}\,nm$

Work Step by Step

Mass $m=2.5\,g=2.5\times10^{-3}\,kg$ Velocity $u=\frac{35\,mi}{h}=\frac{35\,mi}{1\,h}\times\frac{1\,h}{3600\,s}\times\frac{1609.344\,m}{1\,mi}=15.6464\,m/s$ Planck's constant $h=6.63\times10^{-34}\,J\cdot s$ Wavelength $\lambda =\frac{h}{mu}=\frac{6.63\times10^{-34}\,J\cdot s}{(2.5\times10^{-3}\,kg)(15.6464\,m/s)}$ $=1.7\times10^{-32}\,m=1.7\times10^{-23}\times10^{-9}\,m$ $=1.7\times10^{-23}\,nm$ (1 nm=$10^{-9}\,m$)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.