Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Review Exercises - Page 411: 73

Answer

$x = \sqrt{y^2-1}$

Work Step by Step

$y = \sqrt{t}$ $t = y^2$ We can replace this value in the equation for $x$: $x = \sqrt{t-1}$ $x = \sqrt{y^2-1}$
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