Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Review Exercises - Page 411: 70

Answer

$r = 2$

Work Step by Step

$x^2+y^2 = 4$ $(r~cos~\theta)^2+(r~sin~\theta)^2 = 4$ $r^2~cos^2~\theta+r^2~sin^2~\theta = 4$ $r^2~(cos^2~\theta+sin^2~\theta) = 4$ $r^2~(1) = 4$ $r^2 = 4$ $r = 2$
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