Answer
$r = 2$
Work Step by Step
$x^2+y^2 = 4$
$(r~cos~\theta)^2+(r~sin~\theta)^2 = 4$
$r^2~cos^2~\theta+r^2~sin^2~\theta = 4$
$r^2~(cos^2~\theta+sin^2~\theta) = 4$
$r^2~(1) = 4$
$r^2 = 4$
$r = 2$
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