Answer
(a) We can see the point plotted on the graph below.
(b) We can write two pairs of polar coordinates for this point:
$(3, 240^{\circ})$
$(-3, 60^{\circ})$
Work Step by Step
$(-\frac{3}{2}, -\frac{3\sqrt{3}}{2})$
(a) We can see the point plotted on the graph below.
(b) $r = \sqrt{(-\frac{3}{2})^2+(-\frac{3\sqrt{3}}{2})^2} = 3$
We can find the angle $\phi$ below the negative x-axis:
$tan~\phi = \frac{\frac{3\sqrt{3}}{2}}{\frac{3}{2}}$
$\phi = arctan(\sqrt{3})$
$\phi = 60^{\circ}$
We can write two pairs of polar coordinates for this point:
$(3, 240^{\circ})$
$(-3, 60^{\circ})$
