Answer
(a) We can see the point plotted on the graph below.
(b) We can write two pairs of polar coordinates for this point:
$(2, 135^{\circ})$
$(-2, 315^{\circ})$
Work Step by Step
$(-\sqrt{2}, \sqrt{2})$
(a) We can see the point plotted on the graph below.
(b) $r = \sqrt{(-\sqrt{2})^2+(\sqrt{2})^2} = 2$
We can find the angle $\phi$ above the negative x-axis:
$tan~\phi = \frac{\sqrt{2}}{\sqrt{2}}$
$\phi = arctan(\frac{\sqrt{2}}{\sqrt{2}})$
$\phi = 45^{\circ}$
We can write two pairs of polar coordinates for this point:
$(2, 135^{\circ})$
$(-2, 315^{\circ})$