Answer
(a) We can see the point plotted on the graph below.
(b) We can write two pairs of polar coordinates for this point:
$(\sqrt{2}, 315^{\circ})$
$(-\sqrt{2}, 135^{\circ})$
Work Step by Step
$(1, -1)$
(a) We can see the point plotted on the graph below.
(b) $r = \sqrt{(1)^2+(-1)^2} = \sqrt{2}$
We can find the angle $x$ below the positive x-axis:
$tan~x = \frac{1}{1}$
$x = arctan(\frac{1}{1})$
$x = 45^{\circ}$
We can write two pairs of polar coordinates for this point:
$(\sqrt{2}, 315^{\circ})$
$(-\sqrt{2}, 135^{\circ})$
