Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.3 The Law of Cosines - 7.3 Exercises - Page 324: 74

Answer

33 cans of paint are needed.

Work Step by Step

We can find the semi-perimeter $S$: $S = \frac{75+68+85}{2} = 114$ We can find the area: $A = \sqrt{S~(S-a)(S-b)(S-c)}$ $A = \sqrt{(114)~(114-75)(114-68)(114-85)}$ $A = \sqrt{(114)~(39)(46)(29)}$ $A = \sqrt{5,930,964}$ $A = 2435.36~m^2$ We can find the number of cans of paint which are required: $\frac{2435.36~m^2}{75~m^2} = 32.5~cans$ Therefore, 33 cans of paint are needed.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.