Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.3 The Law of Cosines - 7.3 Exercises - Page 324: 71

Answer

The triangle has whole number lengths and its area and perimeter is both 36. Therefore, it is a perfect triangle.

Work Step by Step

A triangle is a perfect triangle if it fulfills two requirements. First, a perfect triangle is a triangle whose sides have whole number lengths. Since the triangle in question has sides 9,10 and 17; it fulfills the first requirement. Second, the area of a perfect triangle is numerically equal to its perimeter. Therefore, we find the perimeter and area of the triangle in question and compare the two: Perimeter= Sum of all three sides Perimeter=$9+10+17$ Perimeter=$36$ To find the area, we need to apply the Heron's formula since the length of all three sides is given: To use the Heron's formula, we first need to find the semi-perimeter $s$. We substitute the values of the sides of the triangle in the formula below to find the semi-perimeter $s$: $s=\frac{1}{2}(a+b+c)$ $s=\frac{1}{2}(9+10+17)$ $s=\frac{1}{2}(36)$ $s=18$ Now, we use the Heron's formula to find the area of the triangle: $A=\sqrt{s(s-a)(s-b)(s-c)}$ $A=\sqrt{18(18-9)(18-10)(18-17)}$ $A=\sqrt{18(9)(8)(1)}$ $A=\sqrt{1296}$ $A=36$ Since the area of the triangle is numerically equal to its perimeter, the triangle also fulfills the second requirement. Therefore, it is a perfect triangle.
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