Answer
$$\sin(\pi+x)=-\sin x$$
Work Step by Step
$$X=\sin(\pi+x)$$
According to the identity of the sum of sines:
$$\sin(A+B)=\sin A\cos B+\cos A\sin B$$
Expand $X$:
$$X=\sin\pi\cos x+\cos\pi\sin x$$
$$X=0\cos x+(-1)\sin x$$
$$X=-\sin x$$
Overall,
$$\sin(\pi+x)=-\sin x$$