Answer
$$\cos(\theta-180^\circ)=-\cos\theta$$
Work Step by Step
$$A=\cos(\theta-180^\circ)$$
According to the identity of cosine difference:
$$\cos(A-B)=\cos A\cos B+\sin A\sin B$$
$A$ would be:
$$A=\cos\theta\cos180^\circ+\sin\theta\sin180^\circ$$
$$A=\cos\theta\times(-1)+\sin\theta\times0$$
$$A=-\cos\theta$$