Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Review Exercises - Page 94: 22

Answer

$1$

Work Step by Step

Function Values of Special Angles$: $ $\displaystyle \cos 60^{o}=\frac{1}{2}, \quad \sin 30^{o}=\frac{1}{2}$ $\displaystyle \cos 60^{\mathrm{o}}+2\sin^{2}30^{\mathrm{o}}=\frac{1}{2}+2(\frac{1}{2})^{2}$ $=\displaystyle \frac{1}{2}+2(\frac{1}{4})$ $=\displaystyle \frac{1}{2}+\frac{1}{2}=1$
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