Answer
$p(z\lt2.33)=.9901$
Work Step by Step
According to Table IV, page 773:
$p(0\lt z\leq2.33)=.4901$
$p(z\lt2.33)=p(z\lt0)+p(0\leq z\lt2.33)=p(z\gt0)+p(0\leq z\lt2.33)=.5+.4901=.9901$
Statistics (12th Edition)
by McClave, James T.; Sincich, Terry T.
Published by
Pearson
ISBN 10:
0321755936
ISBN 13:
978-0-32175-593-3
Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Learning the Mechanics - Page 241: 5.26h
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