Answer
$p(z\geq-2.33)=.9901$
Work Step by Step
According to Table IV, page 773:
$p(0\lt z\leq2.33)=.4901$
$p(z\geq-2.33)=p(-2.33\leq z\lt0)+p(z\geq0)=p(0\lt z\leq2.33)+p(z\geq0)=.4901+.5=.9901$
Statistics (12th Edition)
by McClave, James T.; Sincich, Terry T.
Published by
Pearson
ISBN 10:
0321755936
ISBN 13:
978-0-32175-593-3
Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Learning the Mechanics - Page 241: 5.26g
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
