Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Learning the Mechanics - Page 241: 5.26a

Answer

$p(z\gt1.46)=.0721$

Work Step by Step

According to Table IV, page 773: $p(0\lt z\lt1.46)=.4279$ $p(z\gt1.46)=1-p(z\lt1.46)=1-(.5+.4279)=1-.9279=.0721$
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