Answer
$p(x\gt1000)=.0162$
Work Step by Step
$z=\frac{x-\mu}{\sigma}=\frac{1000-605}{185}=2.14$
According to table IV, page 773:
$p(0\lt z\lt2.14)=.4838$
$p(x\gt1000)=p(z\gt2.14)=p(z\lt0)-p(0\lt z\lt2.14)=.5-.4838=.0162$
Statistics (12th Edition)
by McClave, James T.; Sincich, Terry T.
Published by
Pearson
ISBN 10:
0321755936
ISBN 13:
978-0-32175-593-3
Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Applying the Concepts - Basic - Page 243: 5.43d
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