Answer
$p(40\lt x\lt60)=.7528$
Work Step by Step
$z=\frac{x-\mu}{\sigma}=\frac{60-48.5}{8.5}=1.35$
$z=\frac{x-\mu}{\sigma}=\frac{40-48.5}{8.5}=-1$
According to table IV, page 773:
$p(0\lt z\lt1)=.3413$
$p(0\lt z\lt 1.35)=.0948$
$p(40\lt x\lt60)=p(-1\lt z\lt1.35)=p(-1\lt z\lt0)+p(0\lt z\lt1.35)=p(0\lt z\lt1)+p(0\lt z\lt1.35)=.3413+.4115=.7528$