Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.1 The Distance and Midpoint Formulas - F.1 Assess Your Understanding - Page 7: 28

Answer

$d(P_1, P_2)=|a|\sqrt2$

Work Step by Step

The distance between the points $P_1=(x_1, y_1)$ and $P_2=(x_2, y_2)$, is given by the formula: $d(P_1, P_2)=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ If we plug in the coordinates of the two given points given into the formula above, we'd have: $d(P_1, P_2)=\sqrt{(0-a)^2+(0-a)^2}=\sqrt{a^2+a^2}=\sqrt{2a^2}=|a|\sqrt2$
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