Answer
$d=\sqrt{6.89}\approx2.62$
Work Step by Step
Let
$(x_{1},y_{1})=(-0.2, 0.3)$
$(x_{2},y_{2})=(2.3, 1.1)$
Now, $d=\sqrt {(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$
Substitute the given values into the formula above to obtain:
$d= \sqrt {(2.3+0.2)^{2}+(1.1-0.3)^{2}}$
$d=\sqrt {(2.5)^{2}+(0.8)^{2}}$
$d=\sqrt {6.25+0.64}$
$d=\sqrt {6.89}$
$d\approx2.62$