Answer
$cos130^\circ+i\ sin130^\circ$, $cos30^\circ+i\ sin30^\circ$
Work Step by Step
1. Use the given numbers, we have
$z\cdot w=cos(80+50)^\circ+i\ sin(80+50)^\circ=cos130^\circ+i\ sin130^\circ$
2. we have
$\frac{z}{w}=cos(80-50)^\circ+i\ sin(80-50)^\circ=cos30^\circ+i\ sin30^\circ$
