Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 496: 8

Answer

True.

Work Step by Step

True. Start from the left side $LHS=tan\theta\cdot cos\theta=\frac{sin\theta}{cos\theta}\cdot cos\theta=sin\theta=RHS$ when $\theta\ne(2k+1)\frac{\pi}{2}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.