Answer
$ 2csc^2(v)$
Work Step by Step
$\frac{1}{1-cos(v)}+\frac{1}{1+cos(v)}=\frac{1+cos(v)+1-cos(v)}{(1-cos(v))(1+cos(v))}=\frac{2}{1-cos^2(v)}=\frac{2}{sin^2(v)}=2csc^2(v)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 496: 14
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