Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Chapter Review - Review Exercises - Page 458: 9

Answer

$0$

Work Step by Step

We know these trigonometric values $\tan \pi= \tan 180^{\circ} =0 $ and $\sin \pi= \sin 180^{\circ} =0 $ We evaluate the given expression to obtain: $\tan \pi +\sin \pi = \tan 180^{\circ} + \sin 180^{\circ} =0+0 $ or, $=0$
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