Answer
amplitude$=\frac{1}{2}$, period$ =\frac{4\pi}{3}$, phase shift$= \frac{2\pi}{3}$.
See graph.
Work Step by Step
1. Given $y=\frac{1}{2}sin(\frac{3}{2}x-\pi)$, we find the amplitude$=\frac{1}{2}$, period$=\frac{2\pi}{3/2}=\frac{4\pi}{3}$, phase shift$=\frac{\pi}{3/2}=\frac{2\pi}{3}$.
2. See graph.
