Answer
Quadrant I
Work Step by Step
Since $f^{-1} (x)$ is the reflection of $f(x)$ about the line $y=x$, the graph will remain in Quadrant I.
This is because when we reflect the graph of $f(x)$ about the line $y=x$, the inverse will remain in Quadrant I.
In other words, consider the pair of coordinates $(a,b)$ of $f(x)$. These coordinates will both be positive since we are in Quadrant I. The inverse coordinates will then be $(b,a)$, which are also positive and also in Quadrant I.