Answer
$\frac{1}{4},4$.
Work Step by Step
Step 1. Let $u=\sqrt x$, for $f(x)=0$, we have $2u^2-5u+2=0 \Longrightarrow (2u-1)(u-2)=0 \Longrightarrow u=\frac{1}{2},2$
Step 2. For $u=\frac{1}{2}$, we have $\sqrt x=\frac{1}{2}$, thus $x=\frac{1}{4}$.
Step 3. For $u=2$, we have $\sqrt x=2$, thus $x=4$.