Answer
(a) $95$
(b) $127$
(c) $17$
(d) $1$
Work Step by Step
a) $(f\circ g)(4)= f(g(4))=f(2\times4^{2}-1)=f(31)=3\times31+2=95$
b) $(g\circ f)(2)=g(f(2))=g(3\times2+2)=$$g(8)=2\times8^{2}-1=127$
c) $(f\circ f)(1)=f(f(1))=f(3\times1+2)=f(5)=3\times5+2=17$
d) $(g\circ g)(0)=g(g(0))=g(2\times0^{2}-1)=g(-1)=2\times(-1)^{2}-1=1$
