Answer
(a) $98$
(b) $49$
(c) $4$
(d) $4$
Work Step by Step
a) $(f\circ g)(4)= f(g(4))=f(3\times4^{2}+1)=f(49)=2\times49=98$
b) $(g\circ f)(2)=g(f(2))=g(2\times2)=g(4)=3\times4^{2}+1=49$
c) $(f\circ f)(1)=f(f(1))=f(2\times1)=f(2)=2\times2=4$
d) $(g\circ g)(0)=g(g(0))=g(3\times0^{2}+1)=g(1)=3\times1^{2}+1=4$