Answer
$(4, \frac{2\pi}{3})$
Work Step by Step
Use the conversion formulas, we have
$r=\sqrt {(-2)^2+(2\sqrt 3)^2}=4$,
$\theta=tan^{-1}(\frac{2\sqrt 3}{-2})=tan^{-1}(-\sqrt 3)=\frac{2\pi}{3}$
Thus the polar coordinates are $(4, \frac{2\pi}{3})$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.1 Finding Limits Using Tables and Graphs - 13.1 Assess Your Understanding - Page 897: 52
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