Answer
center $(2,-1)$, vertices $(2,-1\pm\sqrt {13})$, foci $(2,-3),(2,1)$
Work Step by Step
1. Based on the given equation, we can identify the center $(2,-1)$ and a vertical major axis.
2. We have $a^2=13, b^2=9$, thus $$c=\sqrt {13-9}=2$
3. The vertices are $(2,-1\pm\sqrt {13})$, foci $(2,-1\pm2)$ or $(2,-3),(2,1)$
