Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.1 Finding Limits Using Tables and Graphs - 13.1 Assess Your Understanding - Page 897: 49

Answer

$4\sqrt 5$ $(4,-7)$

Work Step by Step

1. Given $A(2,-3)$ and $B(6,-11)$, use the distance formula, we have $d_{AB}=\sqrt {(6-2)^2+(-11+3)^2}=\sqrt {80}=4\sqrt 5$ 2. Use the midpoint formula to get $M=(\frac{2+6}{2},\frac{-3-11}{2})=(4,-7)$
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