Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.2 Permutations and Combinations - 12.2 Assess Your Understanding - Page 875: 50

Answer

$5,209,344$

Work Step by Step

Use the combination formula, we have $C(4,2)C(8,3)C(20,5)=(6)(56)(15504)=5,209,344$ possible committee formations.
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