Answer
$C(15,15) = 1$
Work Step by Step
We know, $C(n,r) = \dfrac{n!}{(n-r)!r!}$
In this case,
$C(15,15)
\\= \dfrac{15!}{(15-15)!\times15!}
\\= \dfrac{15!}{0!\times15!}
\\=\dfrac{15!}{15!}
\\=1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 12 - Counting and Probability - Section 12.2 Permutations and Combinations - 12.2 Assess Your Understanding - Page 875: 19
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