Answer
$(2,-5,3)$
Work Step by Step
1. Eliminate $z$ from equations 1 and 3, add up to get $-x+2y=-12$ or $x-2y=12$
2. Eliminate $z$ from equations 1 and 2, multiply eqn1 with 6x3 and add to eqn2 to get
$6x-5y=37$
3. Eliminate $x$ from the above results, multiply -6 to the equation in step1 and add it to that of step2 to get $7y=-35$, thus $y=-5$
4. Use substitution to get $x=2$ and $z=3$, solution $(2,-5,3)$
