Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Cumulative Review - Page 890: 10

Answer

$125$ $700$

Work Step by Step

This is an arithmetic sequence, we have $a_1=-3, d=4$, $a_n=a_1+4(n-1)$ and $S_n=\frac{n}{2}(2a_1+4(n-1))$, thus we have: the 33rd term: $a_{33}=-3+4(33-1)=125$ the sum of the first 20 terms: $S_{20}=\frac{20}{2}(2(-3)+4(20-1))=700$
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