Answer
opens up, vertex $(-2,-9)$,
axis of symmetry $x=-2$,
intercepts $(0,-5),(-5,0),(1,0)$.
See graph.
Work Step by Step
Given $f(x)=x^2+4x-5=(x+2)^2-9$, we can identify that
the graph opens up, with vertex $(-2,-9)$, axis of
symmetry $x=-2$, and intercepts $(0,-5),(-5,0),(1,0)$.
See graph.
