Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.3 Geometric Sequences; Geometric Series - 11.3 Assess Your Understanding - Page 845: 81

Answer

$\frac{\sqrt 3(\sqrt 3+1)(3^{25}-1)}{2}$

Work Step by Step

Based on the given series, we have $r=3^{1/2}$, it is geometric, $S_{50}=\frac{\sqrt 3(3^{50/2}-1)}{\sqrt 3-1}=\frac{\sqrt 3(\sqrt 3+1)(3^{25}-1)}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.