Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.3 Geometric Sequences; Geometric Series - 11.3 Assess Your Understanding - Page 845: 80

Answer

$\text{The sequence is neither arithmetic nor geometric.}$

Work Step by Step

We will check whether the sequence is arithmetic or geometric. (1) A sequence is arithmetic if there exists a common difference $d$ among consecutive terms such as: $d=a_n−a_{n−1}$ (2) A sequence is geometric if there exists a common ratio $r$ among consecutive terms such as: $r=\dfrac{a_n}{a_{n−1}}$ We see that there is no common difference, so the sequence is not a arithmetic. Next, we will check if a common ratio $r$ exists, solve for $r$ for a few pairs of consecutive terms: $r=\dfrac{a_2}{a_1}=\dfrac{1}{1}=1$ and $ r=\dfrac{a_3}{a_2}=\dfrac{2}{1}=2$ We see that the ratios are different, so the sequence is not geometric. Therefore, the sequence is neither arithmetic nor geometric.
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