Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.1 Sequences - 11.1 Assess Your Understanding - Page 829: 96

Answer

$\approx 9.43398115$

Work Step by Step

We apply the given recursive formula to find the approximate value for $\sqrt {89}$ as follows: $$\displaystyle a_0=9 \\ a_1=\frac{1}{2}(a_0+\frac{89}{a_0})=9.44444 \\ a_2=\frac{1}{2}(a_1+\frac{89}{a_1})\approx9.433986 \\ a_3=\frac{1}{2}(a_2+\frac{89}{a_2})\approx9.433981 \\ a_4=\frac{1}{2}(a_3+\frac{89}{a_3})\approx9.4339811 \\a_5=\frac{1}{2}(a_4+\frac{89}{a_4})\approx 9.43398115$$ Therefore, we get the approximate value for $\sqrt{89}=9.43398113206 \approx 9.43398115$
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