Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.1 Sequences - 11.1 Assess Your Understanding - Page 829: 95

Answer

$\approx 4.5825757$

Work Step by Step

We apply the given recursive formula to find the approximate value for $\sqrt {21}$ as follows: $$\displaystyle a_0=4 \\a_1=\frac{1}{2}(a_0+\frac{21}{a_0})=4.625 \\ a_2=\frac{1}{2}(a_1+\frac{21}{a_1})\approx4.58277 \\ a_3=\frac{1}{2}(a_2+\frac{21}{a_2})\approx4.58257 \\a_4=\frac{1}{2}(a_3+\frac{21}{a_3})\approx4.582575 \\ a_5=\frac{1}{2}(a_4+\frac{21}{a_4})\approx4.5825757$$ Therefore, we get the approximate value for $\sqrt{21}=4.58257569496 \approx 4.5825757$
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