Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.1 Sequences - 11.1 Assess Your Understanding - Page 829: 93

Answer

$\approx 2.236$

Work Step by Step

We apply the given recursive formula to find the approximate value for $\sqrt 5$ as follows: $$\displaystyle a_0=2 \\ a_1=\frac{1}{2}(a_0+\frac{5}{a_0})\approx2.25 \\a_2=\frac{1}{2}(a_1+\frac{5}{a_1})\approx2.23611 \\ a_3=\frac{1}{2}(a_2+\frac{5}{a_2})\approx2.23606 \\a_4=\frac{1}{2}(a_3+\frac{5}{a_3})\approx2.2423 \\ a_5=\frac{1}{2}(a_4+\frac{5}{a_4})\approx2.236$$ Therefore, we get the approximate value for $\sqrt{5}=2.2360679775 \approx 2.236$.
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