Answer
$820$
Work Step by Step
Recall the formula: $\sum_{i=1}^{n}k = \dfrac{n(n+1)}{2}$
Apply the formula above to obtain:
$\sum_{k=1}^{40} k = \dfrac{40(40+1)}{2} \\=\dfrac{(40) (41)}{2} \\=820$
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