Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.1 Sequences - 11.1 Assess Your Understanding - Page 828: 71

Answer

$820$

Work Step by Step

Recall the formula: $\sum_{i=1}^{n}k = \dfrac{n(n+1)}{2}$ Apply the formula above to obtain: $\sum_{k=1}^{40} k = \dfrac{40(40+1)}{2} \\=\dfrac{(40) (41)}{2} \\=820$
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