Answer
$243m^5+810m^4+1080m^3+720m^2+240m+32$
Work Step by Step
Use the Binomial Theorem, we have:
$(3m+2)^5=(3m)^5+5(2)(3m)^4+10(2)^2(3m)^3+10(2)^3(3m)^2+5(2)^4(3m)+(2)^5
=243m^5+810m^4+1080m^3+720m^2+240m+32$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 11 - Sequences; Induction; the Binomial Theorem - Chapter Test - Page 860: 13
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